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Proof step 2 from proof countrefs-lastn-02 (previous step)

lastn(1 + n * m, refs) = r0 ' + refs1, # refs = 2 + n * m + m0, r ∈ refs1, # refs ≤ n * m ⊦ r ∈ refs

User applied rule insert equation

And closed the goal!

Rule argument

[inserteqarg: pos: left 2,F,T,()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m * n = n * m], [CSIMPSEQ : ⊦ m + n ≤ m ↔ n = 0], [CSIMPSEQ : ⊦ m + n = 0 ↔ m = 0 ∧ n = 0], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m])]]