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Proof step 4 from proof countrefs-lastn (previous step)

lastn(i→n(countrefs(i1 ' + ints1)), r1 ' + refs2) = r0 ' + refs1, # refs2 = i→n(countrefs(i1 ' + ints1)) * i→n(i2) + i→n(countrefs(i1 ' + ints1)), 1 + # refs2 < i→n(countrefs(i1 ' + ints1)), 0 ≤ i2, # refs2 ≤ # refs1 ⊦

User applied rule insert equation

And closed the goal!

Rule argument

[inserteqarg: pos: left 2,F,T,()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m + n < m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m])]]