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Proof step 2 from proof countrefs-le-01 (previous step)

# refs = i→n(countrefs((i + 1) ' + ints)), # refs ≤ # refs - i→n(countrefs(ints)), 0 ≤ i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ # refs = i→n(countrefs(i ' + ints)) ∧ 0 < i → ¬ # refs ≤ # refs - i→n(countrefs(ints))

Rule argument

[crewrite-arg: countrefs-le, F, [refs, i, ints] → [refs, i + 1, ints]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])], [EXTRATERMS : (refs, i + 1, ints)]]