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Proof step 12 from proof countrefs-le (previous step)

¬ (countrefs(i ' + ints) ≤ 0 ∧ countrefs(ints) ≤ 0), # refs = i→n(countrefs(i ' + ints)), # refs < i→n(countrefs(ints)), 0 < i, # refs ≤ # refs - i→n(countrefs(ints)), abs(countrefs(i ' + ints)) < abs(countrefs(ints)) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# refs = i→n(countrefs(i ' + ints)), # refs < i→n(countrefs(ints)), 0 < i, # refs ≤ # refs - i→n(countrefs(ints)), abs(countrefs(i ' + ints)) < abs(countrefs(ints)) ⊦ ¬ 0 < countrefs(i ' + ints) ∧ ¬ 0 < countrefs(ints)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]