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Proof step 17 from proof countrefs-le (previous step)

# refs = n + i→n(countrefs(ints)), # refs = i→n(countrefs(i ' + ints)), i→n(countrefs(ints)) ≤ # refs, # refs ≤ n, 0 < i, i→n(countrefs(ints)) ≤ n ⊦

User applied rule insert equation

And obtained the following new goals

Proof step 16:
⊦ countrefs(ints) ≠ 0

Rule argument

[inserteqarg: pos: left 1,F,T,()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m ≤ m + n], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m + n ≤ m ↔ n = 0], [CSIMPSEQ : ⊦ i→n(i) = 0 ↔ i = 0])]]