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Proof step 20 from proof countrefs-le (conclusion)

⊦ # refs = i→n(countrefs(i ' + ints)) ∧ 0 < i → ¬ # refs ≤ # refs - i→n(countrefs(ints))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
# refs = i→n(countrefs(i ' + ints)), # refs ≤ # refs - i→n(countrefs(ints)), 0 < i ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]