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Proof step 15 from proof countrefs-ls (previous step)

0 < i, 1 < countrefs([]), 0 < countrefs([]) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ # ints ≤ 1 → countrefs(ints) = 1

Rule argument

[crewrite-arg: countrefs-base, F, [ints] → [[]]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # [] = 0])], [EXTRATERMS : ([])]]