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Proof step 6 from proof countrefs-ls (previous step)

countrefs(ints) * (i - 1) < 0, countrefs(ints) * (i - 1) < (~1), 0 < i, countrefs(ints) * (i - 1) < i ⊦ ints = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,i0 = i - j ↔ i = i0 + j ,[i, j, i0] → [i, 1, i0] ,T ,int-abs , ,elim-sub ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i * j = j * i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i < j + 1 ↔ i ≤ j], [CSIMPSEQ : ⊦ i < 0 ∧ 0 ≤ j → i ≤ j], [CSIMPSEQ : ⊦ 0 ≤ i → (i * j < 0 ↔ ¬ ¬ (j < 0 ∧ i ≠ 0))], [CSIMPSEQ : ⊦ i * j * j0 = (i * j) * j0], [CSIMPELIM : ⊦ i0 = i - j ↔ i = i0 + j])], [EXTRATERMS : (i, 1, i0)]]