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Proof step 10 from proof countrefs-not-zero-01 (previous step)

countrefs(i ' + ints0) = 0 ⊦ countrefs(ints0) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ # ints ≤ 1 → countrefs(ints) = 1
Proof step 9:
¬ # (i ' + ints0) ≤ 1, countrefs(i ' + ints0) = 0 ⊦ countrefs(ints0) = 0

Rule argument

[crewrite-arg: countrefs-base, F, [ints] → [i ' + ints0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (i ' + ints0)]]