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Proof step 8 from proof countrefs-not-zero (previous step)

0 ≤ countrefs(ints0), countrefs(i ' + ints0) < 0 ⊦ ints0 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ # ints > 1 ∧ ints .first ≤ 0 → countrefs(ints) = 1
Proof step 7:
¬ (# (i ' + ints0) > 1 ∧ (i ' + ints0) .first ≤ 0), 0 ≤ countrefs(ints0), countrefs(i ' + ints0) < 0 ⊦ ints0 = []

Rule argument

[crewrite-arg: countrefs-zero-01, F, [ints] → [i ' + ints0]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # (ints + ints0) = # ints + # ints0], [CSIMPSEQ : ⊦ # i ' = 0 +1], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ m > n ↔ n < m], [CSIMPSEQ : ⊦ 1 < m ↔ ¬ (m = 0 ∨ m = 1)], [CSIMPSEQ : ⊦ m + 1 ≠ 0], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1], [CSIMPSEQ : ⊦ # ints = 0 ↔ ints = []], [CSIMPSEQ : ⊦ (i ' + ints) .first = i])], [EXTRATERMS : (i ' + ints0)]]