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Proof step 12 from proof countrefs-rec-02 (conclusion)

⊦ 0 ≤ i2 → i→n(countrefs(i2 ' + i1 ' + ints1)) = i→n(countrefs(i1 ' + ints1)) * i→n(i2) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 ≤ i2 ⊦ i→n(countrefs(i2 ' + i1 ' + ints1)) = i→n(countrefs(i1 ' + ints1)) * i→n(i2) + 1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j])]]