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Proof step 11 from proof getcountdims (conclusion)

⊦ n→i(# getdims(ints)) + countdims(ints, i) = n→i(# ints) + i

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ countdims([], i) = i
Proof step 2:
⊦ getdims([]) = []
Proof step 10:
∀ i. n→i(# getdims(ints0)) + countdims(ints0, i) = n→i(# ints0) + i ⊦ n→i(# getdims(i0 + ints0)) + countdims(i0 + ints0, i) = n→i(# (i0 + ints0)) + i

Rule argument

[VARWITHVARSEQSARG : ints, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : intlist generated by [], +;], [CSIMPSEQ : ⊦ # [] = 0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])]]