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Proof step 75 from proof multg-at-ref (conclusion)

r ≠ r0, ¬ r0 ∈ refs, i→n(countrefs2(ints)) ≤ # refs ⊦ (addarraymultlist(r, ty, st, refs, ints, ints0, i)[r0 -- sk]) = st[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 74:
i→n(countrefs2(ints)) ≤ # refs ⊦ r = r0, (addarraymultlist(r, ty, st, refs, ints, ints0, i)[r0 -- sk]) = st[r0 -- sk], r0 ∈ refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]