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Proof step 14 from proof multi-isarrayref-notin (previous step)

# refs = i→n(countrefs(i ' + ints0)), i ≤ i0, 0 ≤ i, posints(ints0), 0 ≤ i0 ⊦ (∀ j0. ¬ j0 < 0 ∧ ¬ j ≤ j0 → r -- j0 ' ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)) ↔ is_arrayref(r, j, st), r ∈ refs, 0 ∈ (i0 ' + ints0) .butlast

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)
Proof step 13:
# refs = i→n(countrefs(i ' + ints0)), i ≤ i0, 0 ≤ i, posints(ints0), 0 ≤ i0 ⊦ (∀ j0. ¬ j0 < 0 ∧ ¬ j ≤ j0 → r -- j0 ' ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)) ↔ (∀ j0. 0 ≤ j0 ∧ j0 < j → r -- j0 ' ∈ st), r ∈ refs, 0 ∈ (i0 ' + ints0) .butlast

Rule argument

[speclemmaarg: ,is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st) ,[st, i, r] → [st, j, r] ,F ,storearrays , ,is_arrayref ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, j, r)]]