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Proof step 31 from proof multi-isarrayref (previous step)

1 + # refs ≤ # refs1, # refs1 = 1 + # refs + i→n(i1) * # refs + i→n(i1), lastn(1 + # refs, refs1) = r1 ' + refs, 1 + # refs = i→n(countrefs(i0 ' + ints1)), # refs ≤ # refs1, r ∈ refs1, posints(ints1), 0 ≤ i0, 0 ≤ n→i(# acc) + i1, 0 ≤ i1, ∀ st, ty, ints, i, acc, r, refs0. # refs0 < # (r0 + refs1) → ( true → ( r ∈ refs0 ∧ n→i(# acc) + i = ints .first ∧ # refs0 = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first → is_arrayref(r, (addmultiarrays(refs0, i, acc, ty, ints, st)[r -- _length]) .intval, addmultiarrays(refs0, i, acc, ty, ints, st)))) ⊦ r = r0, (~1) = n→i(# acc) + i1, (~1) = i1, r = r1, r ∈ firstn(i→n(i1) * # refs + i→n(i1), refs1), r ∈ refs, 0 ∈ (i0 ' + ints1) .butlast, is_arrayref (r, (addmultiarrays(r1 ' + refs, i0, [], ty, i0 ' + ints1, st)[r -- _length]) .intval, addmultiarrays(r1 ' + refs, i0, [], ty, i0 ' + ints1, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: , lastn(n, refs) = refs0 ∧ ¬ r ∈ refs0 ∧ r ∈ refs ∧ n ≤ # refs ∧ m = # refs - n → r ∈ firstn(m, refs) ,[n, refs, refs0, r, m] → [1 + # refs, refs1, r1 ' + refs, r, i→n(i1) * # refs + i→n(i1)] ,F ,list-del ,references ,lastn-firstn-in-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (1 + # refs, refs1, r1 ' + refs, r, i→n(i1) * # refs + i→n(i1))]]