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Proof step 38 from proof multi-length-first (previous step)

ints = i0 + ints0, # refs + 1 = i→n(countrefs(i ' + ints0)), n→i(# acc) + i = i0, posints(ints), 0 ≤ i, ∀ st, ty, r, acc, ints, i, refs0. # refs0 < # refs → ( true → ( # refs0 + 1 = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first ∧ n→i(# acc) + i = ints .first → (addmultiarrays(r ' + refs0, i, acc, ty, ints, st)[r -- _length]) = intval(ints .first))) ⊦ (addmultiarrays(r ' + refs, i, acc, ty, ints, st)[r -- _length]) = intval(i0), ints = [], 0 ∈ ints .butlast

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
# refs + 1 = i→n(countrefs(i ' + ints0)), 0 ≤ i, posints(ints0), 0 ≤ n→i(# acc) + i, ∀ st, ty, r, acc, ints, i, refs0. # refs0 < # refs → ( true → ( # refs0 + 1 = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first ∧ n→i(# acc) + i = ints .first → (addmultiarrays(r ' + refs0, i, acc, ty, ints, st)[r -- _length]) = intval(ints .first))) ⊦ (addmultiarrays(r ' + refs, i, acc, ty, (n→i(# acc) + i) ' + ints0, st)[r -- _length]) = intval(n→i(# acc) + i), 0 ∈ ((n→i(# acc) + i) ' + ints0) .butlast

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPSEQ : ⊦ posints(i ' + ints) ↔ 0 ≤ i ∧ posints(ints)], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ i ' + ints ≠ []], [CSIMPSEQ : ⊦ i + ints = i ' + ints])]]