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Proof step 10 from proof multi-newref (conclusion)

⊦ ¬ r ∈ refs ∧ # refs = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first → (newref(r, addmultiarrays(refs, i, acc, ty, ints, st)) ↔ newref(r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# refs = i→n(countrefs(i ' + ints .rest)), posints(ints), i ≤ ints .first, 0 ≤ i, 0 ≤ ints .first ⊦ newref(r, addmultiarrays(refs, i, acc, ty, ints, st)) ↔ newref(r, st), ints = [], 0 ∈ ints .butlast, r ∈ refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j])]]