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Proof step 19 from proof multi-newrefs (conclusion)

⊦ # refs = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first ∧ list2set(refs) ∩ list2set(refs0) = ∅ → (is_newref_list(refs0, addmultiarrays(refs, i, acc, ty, ints, st)) ↔ is_newref_list(refs0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# refs = i→n(countrefs(i ' + ints .rest)), list2set(refs) ∩ list2set(refs0) = ∅, posints(ints), i ≤ ints .first, 0 ≤ i, 0 ≤ ints .first ⊦ is_newref_list(refs0, addmultiarrays(refs, i, acc, ty, ints, st)) ↔ is_newref_list(refs0, st), ints = [], 0 ∈ ints .butlast

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j])]]