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Proof step 11 from proof multi-refin-other (previous step)

∃ sk. r -- sk ∈ st, # refs = i→n(countrefs(i ' + ints0)), i ≤ i0, 0 ≤ i, posints(ints0), 0 ≤ i0 ⊦ ∃ sk. r -- sk ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st), r ∈ refs, 0 ∈ (i0 ' + ints0) .butlast

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# refs = i→n(countrefs(i ' + ints0)), r -- sk ∈ st, i ≤ i0, 0 ≤ i, posints(ints0), 0 ≤ i0, r ∈ st ⊦ r ∈ refs, 0 ∈ (i0 ' + ints0) .butlast, ∃ sk. r -- sk ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]