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Proof step 4 from proof multi-refin-other (previous step)

# refs = i→n(countrefs(i ' + ints0)), r -- sk ∈ st, 0 ≤ i, posints(ints0), 0 ≤ i0, r ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st), i ≤ i0, r ∈ st ⊦ 0 ∈ (i0 ' + ints0) .butlast, r ∈ refs, ∃ sk. r -- sk ∈ st

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 3, [QUANTTERMLIST : (sk)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk)]]