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Proof step 12 from proof multi-subset (previous step)

rk ∈ st ∧ # refs = i→n(countrefs(i ' + (i0 ' + ints0) .rest)) ∧ i0 ' + ints0 ≠ [] ∧ 0 ≤ i ∧ posints(i0 ' + ints0) ∧ ¬ 0 ∈ (i0 ' + ints0) .butlast ∧ i ≤ (i0 ' + ints0) .first, # refs = i→n(countrefs(i ' + ints0)), 0 ≤ i0, posints(ints0), is_newref_list(refs, st), 0 ≤ i, i ≤ i0, rk ∈ st ⊦ 0 ∈ (i0 ' + ints0) .butlast, true ∧ st[rk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# refs = i→n(countrefs(i ' + ints0)), 0 ≤ i0, posints(ints0), is_newref_list(refs, st), 0 ≤ i, rk ∈ st, i ≤ i0 ⊦ st[rk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[rk]), 0 ∈ (i0 ' + ints0) .butlast

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (i ' + ints) .first = i], [CSIMPSEQ : ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j], [CSIMPSEQ : ⊦ posints(i ' + ints) ↔ 0 ≤ i ∧ posints(ints)], [CSIMPSEQ : ⊦ i ' + ints ≠ []], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ (i ' + ints) .rest = ints])]]