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Proof step 14 from proof multi-subset (previous step)

# refs = i→n(countrefs(i ' + ints0)), i ≤ i0, 0 ≤ i, is_newref_list(refs, st), posints(ints0), 0 ≤ i0 ⊦ ∀ rk. rk ∈ st → rk ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st) ∧ st[rk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[rk]), 0 ∈ (i0 ' + ints0) .butlast

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
# refs = i→n(countrefs(i ' + ints0)), 0 ≤ i0, posints(ints0), is_newref_list(refs, st), 0 ≤ i, i ≤ i0, rk ∈ st ⊦ 0 ∈ (i0 ' + ints0) .butlast, rk ∈ addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st) ∧ st[rk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]