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Proof step 2 from proof multi-subset (previous step)

⊦ rk ∈ st ∧ # refs = i→n(countrefs(i ' + ints .rest)) ∧ ints ≠ [] ∧ 0 ≤ i ∧ posints(ints) ∧ ¬ 0 ∈ ints .butlast ∧ i ≤ ints .first → rk ∈ addmultiarrays(refs, i, acc, ty, ints, st)

Lemma multi-refin