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Proof step 6 from proof multi-subset (previous step)

# refs = i→n(countrefs(i ' + ints0)), 0 ≤ i0, posints(ints0), ¬ dups(refs) ∧ (∀ r. r ∈ refs → newref(r, st)), 0 ≤ i, r -- sk ∈ st, i ≤ i0, r ∈ st, r ∈ refs ⊦ st[r -- sk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[r -- sk]), 0 ∈ (i0 ' + ints0) .butlast

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# refs = i→n(countrefs(i ' + ints0)), r ∈ refs, r ∈ st, i ≤ i0, r -- sk ∈ st, 0 ≤ i, posints(ints0), 0 ≤ i0, ∀ r. r ∈ refs → newref(r, st) ⊦ st[r -- sk] = (addmultiarrays(refs, i, acc, ty, i0 ' + ints0, st)[r -- sk]), dups(refs), 0 ∈ (i0 ' + ints0) .butlast

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]