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Proof step 2 from proof exactref-put (conclusion)

⊦ rk .ref ≠ r ∧ exactreftype(refval(r), ty, st) → exactreftype(refval(r), ty, st[rk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ rk .ref ≠ r ∧ ¬ exactreftype(refval(r), ty, st[rk, val]) → ¬ exactreftype(refval(r), ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]