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Proof step 11 from proof gengfts (conclusion)

⊦ sk ≠ _type ∧ goodfieldandtype(r, sk, st) ∧ oktype(val, sk .fs .type, st) → (goodfieldsandtypes(r0, sks, st[r -- sk, val]) ↔ goodfieldsandtypes(r0, sks, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
oktype(val, sk .fs .type, st), goodfieldandtype(r, sk, st) ⊦ sk = _type, goodfieldsandtypes(r0, sks, st[r -- sk, val]) ↔ goodfieldsandtypes(r0, sks, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]