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Proof step 3 from proof getarray-subset-01 (previous step)

st ⊆ st0, type∃(str, st[r -- _type] .type), is_array(r, st) ⊦ getarray(r, st) = getarray(r, st0), st[r -- _type] .type .jtelemtype = abstract_type, st[r -- _type] .type .jtelemtype = void_type

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ st ⊆ st0 ∧ is_array(r, st) → getarray(r, st) = getarray(r, st0)

Rule argument

[crewrite-arg: getarray-subset, F, [st, st0, r] → [st, st0, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, st0, r)]]