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Proof step 47 from proof getarray-subset (previous step)

st[r -- _type] .type = mkarraytype(ty), okarray(r, ty, st0), r ∈ st0, 0 < st0[r -- _length] .intval, n < i→n(st0[r -- _length] .intval), r -- _length ∈ st, r -- _type ∈ st, is_typevalue(st[r -- _type]), okarray(r, ty, st), st ⊆ st0, n < # getarray(r, st0), r ∈ st ⊦ getarray(r, st0) = [], st0[r -- _length] .intval = 0, noval = st0[r -- n→i(n) '], r = jvmref, r -- n→i(n) ' ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 46:
st[r -- _type] = typeval(ty0), ty0 = mkarraytype(ty), okarray(r, ty, st0), r ∈ st0, 0 < st0[r -- _length] .intval, n < i→n(st0[r -- _length] .intval), r -- _length ∈ st, r -- _type ∈ st, is_typevalue(st[r -- _type]), okarray(r, ty, st), st ⊆ st0, n < # getarray(r, st0), r ∈ st ⊦ getarray(r, st0) = [], st0[r -- _length] .intval = 0, noval = st0[r -- n→i(n) '], r = jvmref, r -- n→i(n) ' ∈ st

Rule argument

[speclemmaarg: ,is_typevalue(val) → (ty = val .type ↔ val = typeval(ty)) ,[val, ty] → [st[r -- _type], ty0] ,T ,javavalue , ,elim-10 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_typevalue(val) → ( ty = val .type ↔ val = typeval(ty))])], [EXTRATERMS : (st[r -- _type], ty0)]]