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Proof step 56 from proof getarray-subset (previous step)

n < # getarray(r, st0), st ⊆ st0, is_array(r, st), r -- _length ∈ st, r ∈ st, n < i→n(st0[r -- _length] .intval), 0 < st0[r -- _length] .intval ⊦ st[r -- n→i(n) '] = st0[r -- n→i(n) '], st0[r -- _length] .intval = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
0 < st0[r -- _length] .intval, n < i→n(st0[r -- _length] .intval), r ∈ st, r -- _length ∈ st, is_array(r, st), st ⊆ st0, n < # getarray(r, st0) ⊦ st0[r -- _length] .intval = 0, st[r -- n→i(n) '] = st0[r -- n→i(n) '], getarray(r, st0) = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # vals = 0 ↔ vals = []], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]