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Proof step 61 from proof getarray-subset (previous step)

0 ≤ st[r -- _length] .intval, is_array(r, st), st ⊆ st0 ⊦ i→n(st[r -- _length] .intval) = # getarray(r, st0) ∧ (n < i→n(st[r -- _length] .intval) → st[r -- n→i(n) '] = (getarray(r, st0)[n]))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 ≤ st[r -- _length] .intval → # getarray(r, st) = i→n(st[r -- _length] .intval)
Proof step 8:
¬ 0 ≤ st0[r -- _length] .intval, 0 ≤ st[r -- _length] .intval, is_array(r, st), st ⊆ st0 ⊦ i→n(st[r -- _length] .intval) = # getarray(r, st0) ∧ (n < i→n(st[r -- _length] .intval) → st[r -- n→i(n) '] = (getarray(r, st0)[n]))
Proof step 60:
0 ≤ st0[r -- _length] .intval, 0 ≤ st[r -- _length] .intval, is_array(r, st), st ⊆ st0 ⊦ i→n(st[r -- _length] .intval) = i→n(st0[r -- _length] .intval) ∧ (n < i→n(st[r -- _length] .intval) → st[r -- n→i(n) '] = (getarray(r, st0)[n]))

Rule argument

[speclemmaarg: , 0 ≤ st[r -- _length] .intval → # getarray(r, st) = i→n(st[r -- _length] .intval) ,[st, r] → [st0, r] ,F ,storearrays , ,getarray-length ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, r)]]