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Proof step 7 from proof getarray-subset (previous step)

st0[r -- _length] .intval < 0, 0 ≤ st[r -- _length] .intval, st ⊆ st0, is_array(r, st) ⊦ i→n(st[r -- _length] .intval) = # getarray(r, st0) ∧ (n < i→n(st[r -- _length] .intval) → st[r -- n→i(n) '] = (getarray(r, st0)[n]))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk]
Proof step 6:
⊦ ¬ r -- _length ∈ st → ¬ is_array(r, st)

Rule argument

[speclemmaarg: ,rk ∈ st ∧ st ⊆ st1 → st[rk] = st1[rk] ,[rk, st, st1] → [r -- _length, st, st0] ,F ,store ,javastore ,subset-elem-eq ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ ¬ rk ∈ st → st[rk] = ∅[rk]], [CSIMPSEQ : ⊦ ∅[rk] = noval])], [EXTRATERMS : (r -- _length, st, st0)]]