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Proof step 28 from proof getbar-subset (conclusion)

⊦ st ⊆ st0 ∧ okbytearray(r, st) → getbytearray(r, st) = getbytearray(r, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
okbytearray(r, st), st ⊆ st0 ⊦ getbytearray(r, st) = getbytearray(r, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]