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Proof step 19 from proof getintarray-subset (conclusion)
⊦ st ⊆ st0 ∧ is_array(r, st) → getintarray(r, st) = getintarray(r, st0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 18
:
is_array(r, st), st ⊆ st0 ⊦ getintarray(r, st) = getintarray(r, st0)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]