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Proof step 4 from proof getkeys-one (previous step)

fv = sk × val ⊦ fv ' .keys = sk '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ (sk × val) ' .keys = sk '

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]