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Proof step 5 from proof gft-not (conclusion)

sk0 ≠ _type ∧ is_fskey(sk0) ∧ oktype(val, sk0 .fs .type, st) ⊦ ¬ goodfieldandtype(r, sk, st[r0 -- sk0, val]) → ¬ goodfieldandtype(r, sk, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
oktype(val, sk0 .fs .type, st), is_fskey(sk0), goodfieldandtype(r, sk, st) ⊦ sk0 = _type, goodfieldandtype(r, sk, st[r0 -- sk0, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]