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Proof step 3 from proof gft (conclusion)

sk0 ≠ _type ⊦ r ≠ r0 → (goodfieldandtype(r, sk, st[r0 -- sk0, val]) ↔ goodfieldandtype(r, sk, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (goodfieldandtype(r, sk, st[r0 -- sk0, val]) ↔ goodfieldandtype(r, sk, st))
Proof step 2:
⊦ goodfieldandtype(r, sk, st) ↔ is_fskey(sk) ∧ r -- sk ∈ st ∧ okval(st[r -- sk], sk .fs .type)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]