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Proof step 2 from proof gfts-in (previous step)

goodfieldandtype(r, sk, st), goodfieldsandtypes(r, sks0, st), sk0 ∈ sks0, ∀ sk, r, st. sk ∈ sks0 ∧ goodfieldsandtypes(r, sks0, st) → goodfieldandtype(r, sk, st) ⊦ goodfieldandtype(r, sk0, st)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (sk0, r, st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk0, r, st)]]