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Proof step 12 from proof gfts-null (conclusion)

⊦ sk ≠ _type ∧ ¬ sk ∈ sks → (goodfieldsandtypes(r0, sks, st[jvmref -- sk, val]) ↔ goodfieldsandtypes(r0, sks, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ sk = _type, goodfieldsandtypes(r0, sks, st[jvmref -- sk, val]) ↔ goodfieldsandtypes(r0, sks, st), sk ∈ sks

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]