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Proof step 10 from proof gfts-put (conclusion)

⊦ r ≠ r0 → (goodfieldsandtypes(r, sks, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ r = r0, goodfieldsandtypes(r, sks, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]