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Proof step 7 from proof gfts-put (previous step)

∀ r, r0, st, sk0, val. r = r0 ∨ (goodfieldsandtypes(r, sks0, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks0, st)) ⊦ r = r0, goodfieldandtype(r, sk, st[r0 -- sk0, val]) ∧ goodfieldsandtypes(r, sks0, st[r0 -- sk0, val]) ↔ goodfieldandtype(r, sk, st) ∧ goodfieldsandtypes(r, sks0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ r ≠ r0 → (goodfieldandtype(r, sk, st[r0 -- sk0, val]) ↔ goodfieldandtype(r, sk, st))
Proof step 6:
r ≠ r0, ∀ r, r0, st, sk0, val. r = r0 ∨ (goodfieldsandtypes(r, sks0, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks0, st)) ⊦ r = r0, goodfieldandtype(r, sk, st) ∧ goodfieldsandtypes(r, sks0, st[r0 -- sk0, val]) ↔ goodfieldandtype(r, sk, st) ∧ goodfieldsandtypes(r, sks0, st)

Rule argument

[crewrite-arg: gft-put , F , [val, sk0, r0, st, sk, r] → [val, sk0, r0, st, sk, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val, sk0, r0, st, sk, r)]]