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Proof step 2 from proof gfts (conclusion)

sk0 ≠ _type ⊦ r ≠ r0 → (goodfieldsandtypes(r, sks, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (goodfieldsandtypes(r, sks, st[r0 -- sk0, val]) ↔ goodfieldsandtypes(r, sks, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]