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Proof step 11 from proof infis-jvmref (previous step)

∀ r, st, sk, val. r = jvmref ∨ (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ⊦ r = jvmref ∨ (fv + fis0 ∈ st[r -- sk, val] ↔ fv + fis0 ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ r, st, sk, val. r = jvmref ∨ (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ⊦ r = jvmref, fv ' + fis0 ∈ st[r -- sk, val] ↔ fv ' + fis0 ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ fv + fis = fv ' + fis])]]