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Proof step 5 from proof infis-notin-01 (previous step)

∀ st, r, sk, val. (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ∨ sk ∈ fis0 ⊦ fv ' + fis0 ∈ st[r -- sk, val] ↔ fv ' + fis0 ∈ st, sk ∈ fv ' + fis0

User applied rule structural induction

And obtained the following new goals

Proof step 4:
⊦ (∀ st, r, sk, val. (fis0 ∈ st[r -- sk, val] ↔ fis0 ∈ st) ∨ sk ∈ fis0) → ((sk × val) ' + fis0 ∈ st[r -- sk0, val0] ↔ (sk × val) ' + fis0 ∈ st) ∨ sk0 ∈ (sk × val) ' + fis0

Rule argument

[VARWITHFMAVARSARG : fv, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : fieldvalue generated by ×;])]]