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Proof step 8 from proof infis-notin-01 (conclusion)

⊦ ¬ sk ∈ fis → (fis ∈ st[r -- sk, val] ↔ fis ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]