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Proof step 10 from proof instore-afterputs (previous step)

r -- sk1 ∈ st, unique_al(fis0), r -- sk ∈ st, r ∈ st, instore(r, class, fis0, st), ∀ r0, st0, sk0, class0, r2. r0 ∈ st0 ∧ r0 -- sk0 ∈ st0 ∧ instore(r0, class0, fis0, st0) → _type = sk0 ∨ sk0 ∈ fis0 ∨ instore(r0, class0, fis0, st0[r0 -- sk0, refval(r2)]) ⊦ _type = sk1, sk = sk1, _type = sk, instore(r, class, fis0, st[r -- sk, refval(r1)]), sk ∈ fis0, sk1 ∈ fis0, _type ∈ fis0

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 6, [extquanttermlist: (r, st, sk, class, r1) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, st, sk, class, r1)]]