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Proof step 6 from proof instore-null (previous step)

st[jvmref -- fv .1] = fv .2, instore(jvmref, class, fis0, st), jvmref -- fv .1 ∈ st, jvmref ∈ st, ∀ class, st. ¬ instore(jvmref, class, fis0, st) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
fv = sk × val, st[jvmref -- sk] = val, instore(jvmref, class, fis0, st), jvmref -- sk ∈ st, jvmref ∈ st, ∀ class, st. ¬ instore(jvmref, class, fis0, st) ⊦

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]