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Proof step 4 from proof instore-rec-03 (previous step)

⊦ instore(r, class, fv ' + fis, st) ↔ r -- fv .1 ∈ st ∧ st[r -- fv .1] = fv .2 ∧ instore(r, class, fis, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
fv = sk × val ⊦ instore(r, class, fv ' + fis, st) ↔ r -- sk ∈ st ∧ st[r -- sk] = val ∧ instore(r, class, fis, st)

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]