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Proof step 5 from proof is_array-abstract (conclusion)

⊦ is_array(str, r, st) → st[r -- _type] .type .type ≠ abstract_type

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ is_array(str, r, st) ↔ ¬ ¬ ( type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st))
Proof step 4:
st[r -- _type] .type .type = abstract_type, type∃(str, st[r -- _type] .type), is_array(r, st) ⊦ st[r -- _type] .type .jtelemtype = void_type, st[r -- _type] .type .jtelemtype = abstract_type

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]