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Proof step 3 from proof is_array-put-01 (conclusion)

⊦ r ≠ r0 → (is_array(str, r0, st[r -- sk, val]) ↔ is_array(str, r0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ is_array(str, r, st) ↔ ¬ ¬ ( type∃(str, st[r -- _type] .type) ∧ st[r -- _type] .type .jtelemtype ≠ void_type ∧ st[r -- _type] .type .jtelemtype ≠ abstract_type ∧ is_array(r, st))
Proof step 2:
⊦ r ≠ r0 → (is_array(r0, st[r -- sk, val]) ↔ is_array(r0, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → (st[r0 -- sk0, val][r -- sk]) = st[r -- sk]])]]