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Proof step 2 from proof isarray-put-badfield (conclusion)

⊦ is_array(r, st) ∧ fs ' ≠ _type ∧ fs ' ≠ _length → is_array(r, st[r -- fs ', val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ fs ' ≠ _length ∧ fs ' ≠ _type → (is_array(r, st[r0 -- fs ', val]) ↔ is_array(r, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]